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A 0.45kg volleyball travels with a horizontal velocity of 4.0 m/s over the net. You jump...

A 0.45kg volleyball travels with a horizontal velocity of 4.0 m/s over the net. You jump up and hit the ball back with a horzontal velocity of 7.0 m/s. If the contact time is 0.040 s , what was the average force on the ball?

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Answer #2

average force=change in momentum/time

                    =(0.45*7+0.45*4) / 0.04

            =123.75N

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