Question

You have a 4 ohm resistor and a 6 ohm resistor connected in series with a 12.0 volt battery. What is the voltage drop across the 6 ohm resistor (in volts)?

Answer 1

here given

4 $\Omega$ resistor and a 6 $\Omega$ resistor connected in series

with a 12.0 volt battery = V

- - 465 120

4 $\Omega$ and 6 $\Omega$ are connected in series

R_eq = R₁ + R₂

= 4 + 6

R_eq = 10 $\Omega$

using Ohm's Law V = i R_eq

i = V / R_eq

= 12 / 10

i = 1.2 A

the voltage drop across the 6 $\Omega$ resistor is say V ' = ?

V ' = i R_{6 ohm}

= 1.2 x 6

V ' = 7.2 volts

the voltage drop across the 6 $\Omega$ resistor is say V ' = 7.2 volts