Question

er 710 9 You skipped this question in the previous attempt Exercise 9-44 (LO9-1, LO9-2) PrintTech, Inc is introducing a new line of ink-jet printers and would like to promote the number of pages a user can expect from a print cartridge. A sample of 10 cartridges revealed the following number of pages printed (Use Distribution Table) 2,983 3,96 2,518 2,559 2,559 2,622 2,537 2,485 3,236 2,758 Click here for the Excel Deta File a. What is the point estimate of the population mean? (Round your anewer to 2 declmel places) b. Develop a 98% confidence interval for the population mean. (Round your answers to 2 decimal places.) < Prev 2d cr 30 ?ll Next >

Answer 1

Given Data: 2983, 3096, 2510, 2559, 2559, 2622, 2537, 2485, 3236, 2758 We calculate sample mean and std deviation from given data Sample Mean, X - Sample Variance, s2 Sample std dev, s- vs2V74489.166667 272.927035 Point estimate Point estimate of population mean is given by sample mean, 27345-2734 10 2一Σ(x-x)2-670402.5-74489.166667 2734.5 98% CI for μ using t-dist Sample Mean = 2734.5 Sample Standard deviations 272.927035 Sample Size -n- 10 Significance level-α-1-0.98-0.02 Degrees of freedom for t-distribution, d.f.-n -1-9 Critical Value-ta/2df-t0.014-9-2821 (from t-table, two-tails, d.f.-9 ) Margin of Error = E-ta/2,df E 2.821 x 86.307107 272.927035 × 2.821 × V10 Margin of Error, E 243.472349 Limits of 98% confidence interval are given by: Lower limit -- E 2734.5 -243.4723492491.0276512491.028 Upper limitE 2734.5 243.472349 2977.9723492977.972 98% confidence interval is: x E-2734.5士243.472349 (2491.027651, 2977.972349) 98% CI using t-dist: 2491.03 <μ< 2977.97 Note that exact answer using technology is: (2734.5-272.927035426443/SQRT (10) *T.INV (1-(1-0.98)/2,10-1, 2734.5 272.927035426443/SQRT (10) T.INV (1-(1-0.98)/2,10-1 2490.9898559616, 2978.0101440384)