Question

A 65-g sample of silicon is at 21°C. If 800 cal of energy is transferred to the silicon, what is its final temperature?

Answer 1

Heat transferred, Q = m*C*$\Delta$T .....................(1)

here,

m = mass of silicon = 65 gram

C = specific heat of silicon = 0.168 Cal/g°C

$\Delta T$ = (Tfinal - Tinitial)

Tinitial = 21 °C

Q = energy transferred = 800 Cal

{from equation 1}

800 = (65)*(0.168)*(Tfinal - 21)

Tfinal = 94.26 °C