Question

Problem overview. There are a number of ways to normalize, or scale, a set of values. One common normalization technique scales the values so that the minimum value goes to 0, the maximum value goes to 1, and the other values are scaled accordingly. Using this normalization technique, the values of the array below are normalized. Original Array Values -1 -2 2 Normalized Array Values 0.25 0.01.0 0.5 The equation that computes the normalized value from a value xe in the array is the following Normalized xmin, max-min Where minyx and maxx represent the minimum and maximum values in the array x. If you substitute the minimum value for xk in the equation, the numerator is zero, thus, the normalized value for the minimum is zero. If you substitute the maximum value for x in this equation, the numerator and the denominator are the same value; hence the normalized value for the maximum is 1.0. Write and test a main program that has a one-dimensional double array. The maximum number of values that this main array can store is 25. The main program should use several programmer-defined functions. Create programmer-defined functions called get_array, display_array, array_max, array min, and norm. Prompt user to input original array values and print out normalized array values on console.

Answer 1

C PROGRAM:

#include<stdio.h>
void get_array(double x[],int npts)
{
int i;
double d;
printf("Enter %d elements: ",npts);
for(i=0;i<npts;i++)
{
scanf("%lf",&d);
x[i]=d;
}
}

void display_array(double x[],int npts)
{
int i;
for(i=0;i<npts;i++)
{
printf("%.2lf ",x[i]);
}
}

double array_max(double x[25],int npts)
{
int i;
double max=x[0];
for(i=1;i<npts;i++)
{
if(max<x[i])
max=x[i];
}
return(max);
}

double array_min(double x[25],int npts)
{
int i;
double min=x[0];
for(i=1;i<npts;i++)
{
if(min>x[i])
min=x[i];
}
return(min);
}
void norm(double x[25],int npts)
{
int i;
double d;
double min,max;
min=array_min(x,npts);
max=array_max(x,npts);
for(i=0;i<npts;i++)
{
d=x[i];
d=(d-min)/(max-min);
x[i]=d;
}
}

int main()
{
int npt;
double x[25];
printf("Enter number of elements (less than 25): ");
scanf("%d",&npt);
if(npt>=0 && npt<=25)
{
get_array(x,npt);
printf("\nArray elements before normalisation\n");
display_array(x,npt);
norm(x,npt);
printf("\nArray elements after normalisation\n");
display_array(x,npt);
}
else
printf("\nEntered size is not in range");
}
OUTPUT:

Enter number of elements (less than 25): 4 Enter 4 elements: -1 -2 2 0 Array elements before normalisation -1.00-2.00 2.00 0.00 ay elements after normalisation 0.25 0.00 1.00 0.50