Primary consolidation settlement is given by

where,
Sc is settlement
Cc is compression index
H is the thickness of clay layer
is initial void ratio
is initial effective stress
is increase in overburden pressure
Compression index is given by

where,
is change in void ratio
is final effective stress
is initial effective stress
The sample values are calculated as
Initial void ratio is given as 1.
Initial effective stress is given as 400 kN/m2
Increase in overburden pressure is given as 400 kPa
So, change in void ratio will be


The thickness of clay layer is given as 5 m.

Similarly all the values are calculated as

The following are the results (in kPa) of a consolidation test for a clay with a...
I want solution!
3. A laboratory consolidation test was conducted on a specimen collected form the middle of the overconsolidated clay layer and the field consolidation curve is given below. The effective overburden pressure was 40.95 kN/m²at the middle of the clay layer. Calculate a) the recompression index, b) the compression index, and c) the consolidation settlement when the average vertical stress increment at the middle of the clay layer is 50kN/m² due to a foundation load. The thickness of...
TOTAL CONSOLIDATION SETLEMENT Example 1: if the initial void ratio of a clay is e. = 0.9 at initial pressure o =95.8 kN/m, and the compression index of that soil is equal (Cc)=0.052, H=4 m thick, L.L.=42 %. If the clay layer is loaded with infinite load of Ao=287.5 kN/m?, calculate the amount of total settlement of the clay. Сс Se = H .log 1+e, 0 0
2. A future development site is to be preloaded with a 310 kPa surface surcharge to reduce potential settlements in a 12.5-m thick soft clay layer. The soft clay is overlain by a 3-m thick sand layer and underlain by permeable bedrock. The groundwater table is at the sand-clay interface. A sample of the soft clay was extracted from a depth of 9 m and a 1D consolidation and compression test was conducted. Compression data obtained from the test are...
The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 150 sec. How long (in days) will it take for a 3 m thick layer of the same clay in the field under the same pressure increment to reach 75% consolidation? There is an impermeable shale layer at the bottom of the clay layer in the field I. 2. Use Figure 1 for the following Compute the vertical effective...
Please, show step by step and clearly. problem 9.17, (Use 3
equally divided sub-layers for the 15 m clay layer). thanks
please, resolve question 9.17 (Use 3 equally divided sub-layers
for the 15 m clay layer)
9.16 The soil profile and the loading condition are given in the followin n) figure. Total new footing stress including the foundation at z 2 is 400 kN/m2. The soil profile has a rather thick clay layer (15 so that the layer should be...
The oedometer test data below was obtained from a sample of a clay soil when the loading increased from 200 to 400 kN/m² (Table Q8a). Table Q8a Time (min) Time (min) 0.00 0.25 1.00 2.25 4.00 Height (mm) 19.600 19.349 19.178 19.008 18.851 18,727 18.643 18.587 Height (mm) 18.555 18.515 18.505 18.497 18.490 18.483 18.477 18.449 6.25 9.00 12.25 100 400 (a) Using the 'square root of time method' determine the following: immediate compression (mm) primary consolidation (mm) coefficient of...
Deadline: 4pm, Thursday, Oct 10. Hand in the submission electronically in DOC, PDF, or JPEG format) through MyUni Assignment online portal. Late submissions penalised 5% per day. Plagiarism will be penalised severely. 1. (10 marks): This tutorial continues Tutorial No. 4. The soil profile for proposed roadway construction is represented in Figure 1. A soil sample was recovered at A, and was tested in an oedometer device. The test results are provided in Table 1. The void ratio of the...
The following results were obtained from an undrained shear box test carried out on a set of undisturbed soil samples. 0.2 0.8 Normal Load (N) Strain (%) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 0 21 46 70 89 107 121 131 136 138 138 137 136 0.4 Shearing force (N) 0 33 72 110 139 164 180 192 201 210 217 224 230 234 237 236 0 45...
The following results were obtained from an undrained shear box test carried out on a set of undisturbed soil samples. 0.2 0.8 Normal Load (N) Strain (%) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 0 21 46 70 89 107 121 131 136 138 138 137 136 0.4 Shearing force (N) 0 33 72 110 139 164 180 192 201 210 217 224 230 234 237 236 0 45...
Suppose 1000 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. Exactly 495 heads Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. The probability of getting exactly 495...