# If a balloon has a volume of 1.329 L at a pressure of 2.265 atmospheres, what...

If a balloon has a volume of 1.329 L at a pressure of 2.265 atmospheres, what will be the volume of the balloon if the pressure is increased to 4.993 atmospheres?

SOLUTION :

As per Boyle’s Law,

P V = constant

So,

P1 V1 = P2 V2

=> V2 = (P1/P2) * V1

=> V2 = (2.265 / 4.993) * 1.329

=> V2 = 0.6029 L

So, volume of balloon at increased pressure of 4.993 atm  will be 0.6029 L (ANSWER).

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