Question

If a balloon has a volume of 1.329 L at a pressure of 2.265 atmospheres, what will be the volume of the balloon if the pressure is increased to 4.993 atmospheres?

Give your answer to four significant figures.

Answer 1

1. 
   for a given quantity of gas pressure in inversly proportional to volume px 1 (Boyle's law) so Ple=k (k = constant) this Piul = P2 U₂ 2.265 atyn x 1.329 L = 4.993 alfon X V2 = V2 = 2.26581-329 L - 4.993 V₂ = 0.6029 Le four significant Hence volume of balloon at 4.993 atm is 0.6029 L pressure
   

Answer 2

SOLUTION :

As per Boyle’s Law,

P V = constant

So,

P1 V1 = P2 V2

=> V2 = (P1/P2) * V1 

=> V2 = (2.265 / 4.993) * 1.329 

=> V2 = 0.6029 L 

So, volume of balloon at increased pressure of 4.993 atm  will be 0.6029 L (ANSWER).