Given n = 15, p = 0.30
a)

Substituting x values in P(X=x) then we get probabilities and also calculated cumulative probabilities F(x) as follows
| x | P(X=x) | F(x) = P(X<=x) |
| 0 | 0.004748 | 0.004748 |
| 1 | 0.030520 | 0.035268 |
| 2 | 0.091560 | 0.126828 |
| 3 | 0.170040 | 0.296868 |
| 4 | 0.218623 | 0.515491 |
| 5 | 0.206130 | 0.721621 |
| 6 | 0.147236 | 0.868857 |
| 7 | 0.081130 | 0.949987 |
| 8 | 0.034770 | 0.984757 |
| 9 | 0.011590 | 0.996347 |
| 10 | 0.002980 | 0.999328 |
| 11 | 0.000581 | 0.999908 |
| 12 | 0.000083 | 0.999991 |
| 13 | 0.000008 | 0.999999 |
| 14 | 0.000001 | 1.000000 |
| 15 | 0.000000 | 1.000000 |
b) The probability that exactly 10 have part time jobs is 0.002980
i.e. P(X=10 ) = 0.002980
c) P(X >= 8) = 1 - P(X < 8)
= 1 - P(X <= 7)
= 1 - F(7)
= 1 - 0.949987
= 0.050013
d) P(More than 5 do not have part time jobs)
= P(X < = 5) = F(5) = 0.721621
e) Graph:

The shape of the histogram is positive skewed or right skewed distribution
since curve increases fastly and decreases slowly.
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