Question

(20 pts) You are studying the magnetic gyro wheel toy that you just gave your 10- year-old cousin. You are holding it vertically and are considering motion along one of the "arms” as shown in the drawing to the right. The magnetic gyro starts from point A with an angular velocity, o, of 2 revolutions per second and is 0.2 m. above point B (LAB = 0.2 m.). The inner radius of the wheel, ri, is 0.01 m. and the radius of the gyro itself, rw, is 0.04 m. The gyro has a mass of 0.2 kg, and you can consider it to be equivalent to a thin disk of the same radius. The inner wheel doesn't slip. As you probably have seen, the gyro will wrap around point B and climb up the back side of the rod. Determine the height to which the gyro will climb relative to point B. --- LAB A B

Answer 1

but in rolling i.e. Sol": Since wheel does not slip, so there will be friction without slipping work done by friction is zero . So, principle of conservation of enengy consenvation of enengy can be opplied KEA+PEA KEf +PET KEA = ₂ I wr & final will be zeno REF speed will become zeno at maximum height (h) above B! & PE mg A & PE f = mgh I = T 1.7x109 Ź m Cox + Yw%) = { x 0-2% (0.01 +0.04%) kg. m² (for annular disc) 2 rps 2x2 a rad/s 12.566 vad/s { x 1.7x16" X 12.5662 & WA = → KEA 0.013422661 J & PE A 0.2 x 9.81 x 0.2 0.3924 J => 0.2 x 9.818 h 0.3924 +0.013422661 0.40582 2661 h 0.206841 m h 206.8 4mm