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= a and MP: PB = 1:5, In parallelogram OAUB, OẢ = a and OB = b. Let OM where P is on the line segment MB. a Prove that is on

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OAUD ; a parallogram 0A = a, on -ī y AUD atb ID ;.00 : ath By triangle law, :. ; :AOAV OA =a , Aub 20W - atb Om=a/ . Now, op-( бо : 6 pp PU O(J-бр бор - op 5 2 бр : PV =

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