Question

A bent bar is supported with a fixed end at A. There are two forces applied of F1 and F2, to the bar. Replace the two forces with a "Statically Equivalent" resultant force, R. and resultant moment, M, at Point O. Assume "Counter Clockwise" (CCW) is positive for moments. Use the following information: a = 2t, b = 0.5 ft. c = 1.5 ft - 260'. * - 7.2. y = 2.1. F11 = 3 Lbs. IF21 - Lbs. (The units for moment will be "ft-Lbs.") Give your answers in the following orders X-component Rx ? Y-component Ry M.

Answer 1

Assume fi & fy effect will equivalent by force Rt Moment Me Given that b=0.5ft colsft 161 3165 sh 1.: + 1h hangt hrad = R Copp Rome = 369260 +669 16.26 Equivalent system will be {fy Ricone : 5.24 - 0 f, sino, & fsing, = Rsind Rain : 3 Sin 260 + 6 Sin16.26 asino = -1.27 - 0 R= 5.39 obes $ = 13.624° MA = Fisine, xa +FC98, xe + f sin@* (a+b) [ecw is tve) = 3x Sin 260 x 2 +669 16:26 X 1.5 +6 Sin 16.26 X (2+0.5) = 6.93 lbq.ft this MA should be equal to equivalent system. MA = Mo +(-Rsineb x latb)] 6.93 : MO - 5.39 x sin(13.624) X (2,5) Mo = 10.105 lbp.ft

Final Ans will be Rx = 5.24 lbą Ry = -),27 dbp Mo = 10.105 lbp.ft
PLEASE RATE THE ANSWER

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