Question

5-86 A solid steel shaft has a gear with ASTM grade 20 cast-iron hub (E = 14.5 Mpsi) shrink- fitted to it. The shaft diameter is 2.001 + 0.0004 in. The specifications for the gear hub are +0.0004 2.000 -0.0000 in
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Solve problem using equation 3-50 see attached below:

Answer 1

ANSWER:

  Cast iron is a group of iron-carbon alloys with a carbon content greater than 2%.^[1] Its usefulness derives from its relatively low melting temperature. The alloy constituents affect its colour when fractured: white cast iron has carbide impurities which allow cracks to pass straight through, grey cast iron has graphite flakes which deflect a passing crack and initiate countless new cracks as the material breaks, and ductile cast iron has spherical graphite "nodules" which stop the crack from further progressing.
Given 2.000 : +0.0004 -0.0000 in Calculate the diameter interfésence (8) (8) = £ Co-di) Substitute D-2.0001 di- 2.0002 (8) =(2.0001 - 2.000 2 in) =(-0.0001). -0.0004 in Calculate the nominal shoink fit Pressure (P) 8: pl (do 202 +volte (9-v]. Substitule. 8-0.0004 in D-2.0081 im. to = 14:5X106. do -4.00 in Vo = 0.211 Ei30x106 Psi Vi = 0.292 0.0004 in 2.00lin PL 14.00in2+2.000 in 114.5X106 psi 14.00 in 22.001 in 2 (2.001 in 2 2001 30x106psi (2.001 in 2

P= 2.613 kpsi Hence, nominal shrink fit pressure is [2612 kpsi Calculate the tangential slress al oules Badius ((orela) (772o plemento) P-2613 R=1.0005 in 802 in loza - 2.6136(1.0005in)2+(21n)2 7 ( 2in2 (1.0005 in) | Coelo = 43652 kPsi Calculate the radial stress for the outer radius 10-)o) Corto :-p P=2613 (07): -2.613 kpsi from table A-24 ASTM Grade 20 cast iron has a minimum tensile skength (Swi) of 20 kpsi and compressive strength (She lef 83 "Psi Modified Mohí theory | (07) 151

Substitute (oplo :-2613 kpsi (071o :4.3652 kpsi |-2.613 KPS: / ! | 4:3652 kpsil : 0.598531 calculate the factor of M - Sut Safely (m) A Suit - (070 Substitute Sut = 20 kpsi loilo:4.3652 kpsi m 20 kpsi 4.3652 kpsi m24.582)