Question

Question 17 4 pts A balloon originally had a volume of 7.38 L at 85°C and a pressure of 729 torr. To what temperature (°C) must the balloon be changed to reduce its volume to 5.74 Lif the pressure is constant? answer: °C (round final answer to the tenths place) MacBOOK Pro

Answer 1

Answer) Since the pressure is constant. So it is a isobaric process. Hence,,

Constant T

$\frac {V_1}{T_1} = \frac {V_2}{T_2}$

Putting the given values in above equation we get,,

V1= 7.38L , T1= 85°C = 273+85 = 358 K , V2= 5.74L , T2= ___

$\frac{7.38}{358}= \frac {5.74}{T_2}$

$\ T_2= \frac {5.74*358}{7.38}$