Consider the following unbalanced chemical equation. C_5H_12(l) + O_2(g) rightarrow CO_2(g) + H_2O(l) If 41.7 grams...

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Consider the following unbalanced chemical equatio

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Answer 1

Answer #1

C5H12(l) + 8O2(g) ------>5CO2(g) + 6H2O(l)

1 mole of C5H12 are burned in excess of oxygen to form 6 moles of H2O

72gm of C5H12 are burned in excess of oxygen to form 6*18gm of H2O

41.7gm of C5H12 are burned in excess of oxygen to form = 6*18*41.7/72 = 62.55gm of H2O

Answer 2

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