Question

(8c8p4) In the figure, a frictionless roller coaster of mass 1000 kg tops the first hill at height, h = 28 m with speed 8.55 m/s. How much work does its weight do on it from that point to point A?

How much work does its weight do on it from that point to point B?

How much work does its weight do on it from that point to point C?

If the gravitational potential energy of the coaster-Earth system is taken to be zero at point C, what is its value when the coaster is at point B?

If the gravitational potential energy of the coaster-Earth system is taken to be zero at point C, what is its value when the coaster is at point A?

Answer 1

Given: m= 1000 kg h= 28m U= 8.55 mys Part @ work done on it for motion from that point to point A. W=APE = mghs - mgh; = mg Chshi) Here hezhiah : W=OJ Part At point'B'. hp = 5 :.W= mg Ch-5) = mg [] = (1000kg) (9.81 1452) (28 m7 1: W=137340 J] - 11.37 X1055 Part @ At point ºc, h=0 : W= mg Ch-o) = mgh = tloookg) (9.81 m/5²) (28 m) [..W= 2.75 X 1057 Part @ PER= mg () = (1000 kg) (9.8) mys) 28 m) [PER= 1.378105 Part@ PEA = mgh = (100019) (9.81 my52) ( 28 m) = 2.75x10551

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