according to given information Principal amount P = $ 50000
Period n = 20 years
Rate of interest r = 5.6 / 100 = 0.056
Compounding frequency monthly so r = 0.056 / 12 = 0.004667
Number of payments n = 20 x 12 = 240
Now we can use the below formula to find the annual payment (PMT)
PMT = [ p x r x (1+r)n ] / [(1+r)n-1]
PMT = [50000 x 0.004667 x (1+0.00467)240 ] / [(1+0.004667)240-1]
PMT = [233.35 x 3.05931] / [3.05931 - 1]
PMT = [713.8899] / [2.05931]
PMT = $346.664 ~ 346.67
So monthly payment is $ 346.67
So we have to calculate the outstanding loan balance after 60 payments by calculating the present value of the remaining installments, using the present value of an annuity formula
Pmt = Periodic monthly payment = $346.67
i = Mortgage interest rate per period = 0.004667
n = Number of remaining loan payments =240 – 60 = 180
we can use below formula
PV = PMT x [(1 - 1 / (1 + i)n)] / i
PV = 346.67 x [(1 - 1 / (1 + 0.004667)180)] / (0.004667)
PV = 346.67 X [(1-1/(1.004667)180)]/( 0.004667)
PV = 346.67 X [1-1/(2.31198)]/( 0.004667)
PV = 346.67 X [1-0.432529]/( 0.004667)
PV = 346.67 X [0.567471]/( 0.004667)
PV = 346.67 X 121.59224
PV = 42152.38
The balance unpaid after 60 payments made is = $42152.38
Now he agrees to paid $7500 cash payment. So the remaining balance = 42152.38 – 7500 = 34652.38
So the new principal amount p = $34652.38
Interest r = 4.1% = 4.1/100 = 0.041
Compounding period monthly so r = 0.041/12 = 0.00341667
Number of payments = 10yrs = 10 x 12 = 120
Now we can use the below formula to find the annual payment (PMT)
PMT = [ p x r x (1+r)n ] / [(1+r)n-1]
PMT = [34652.38 x 0.00341667 x (1+0.00341667)120 ] / [(1+0.00341667)240-1]
PMT = [118.39574 x 1.505765] / [1.505765- 1]
PMT = [178.27625] / [0.505765]
PMT = $352.4883 ~ 352.5
So monthly payment is $ 352.2
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