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C. U S={P, PP, PPP} D. O S={F, PF, PPF, PPP} E. O S={PPP, FPP, PFP, PPF, FFP, FPF, PFF, FFF} Question 5 Type numbers in the
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Answer #1

Question 5)

Answer)

Probability is given by favorable/total

Total = 5c2 {as 2 members committee from 5} = 10

Favorable = one woman and one men = 3c1*2c1 = 3*2 = 6

Required probability is 6/10 = 0.6

Question 6)

Answer)

Total = 6c2 { 3 women + 3 men} = 15

Favorable = no women = 3c2 = 3

Required probability is 3/15 = 0.2

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