Question

#2b. Suppose that following the CME it is found that at an altitude of 2500 m the electric field has magnitude 1300 N/C and at an altitude of 1500 m the magnitude is 3600 N/C. In both cases the direction of the electric field is vertically toward the earth's surface. Find the net amount of charge (also indicate the sign of the charge) contained in a cube with horizontal faces at altitudes of 2500 and 1500 m. Assume that the surface of the earth is flat and horizontal. Give your answer in the form of "+/-a.bc x 10^(x) C".

Answer 1

from gauss kw we know that E ds = theta sin/elementof The side of a cube = 2500 - 1500 side = 1000m, Delta rea = 1000 times 1000 = 10^6 m^2 E = E_1 + E_2 = 1300 + 3600 = 4900N/c phi = 433.65 times 10^-4 colum theta_in = 4.33 times 10^-2 colum b therefore charge contains the cube = 4.33 times 10^-2colums