Homework Answers
time= distance/ speed
for pulse 1,
t1=L/c( 1/n1 + 1/n2 + 1/n3 + 1/n4)
for pulse 2,
t2=L/c( 2/n5 + 1/n6 + 1/n7)
t1=L/c ( 0.621 + 0.588 + 0.606 + 0.684) =
t2=L/c (1.24 + 0.591 + 0.645)
clearly, pulse 1 takes longer time.
t1= 2.499L/c
t2=2.476L/c
They differ by a multiple of 23 (approx)
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