2NH3(g)--------N2(g)+3H2(g) delta H=160.0 kJ
suppose 50.3 g of NH3 react
calculate how much heat is absorbed or released.
please answer fast and explain each and every concept used in above question Provide proper calculation formula used and concept used
Given change in enthaly is a positive quantity , So the system absorbs heat energy to undergo the decomposition reaction I have attached the details of the solution, just go through it.
2NH3(g)--------N2(g)+3H2(g) delta H=160.0 kJ suppose 50.3 g of NH3 react calculate how much heat is absorbed...
Given the following data for heats of reaction
N2(g) + 3H2(g) ---->
2NH3(g) H
= -91.8 kJ
C(graphite) + 2H2(g) ------->
CH4(g)H
= -74.9kJ
H2(g) + 2C(graphite) + N2(g)
--------> 2HCN(g) H
= 270.3 kJ
Calculate
H for the reaction used to make HCN
CH4(g) + NH3(g) --------> HCN(g) +
3H2(g)
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