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→ XCIOD Question 38 What is Kfor the reaction at 298K? -1.44104 434102 13-10% 14.10 20


For questions 37-39, consider the following redox reaction: 10Cr*(aq) + 6Br03 (aq) +17H_001) — 5C1072 (aq) + 3840 + 34|aF= 0.
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Answer #1

no. Of electrons transferred (n) = 30

E°cell = 0.15 V

Log K = E°cell * n / 0.0591

Log K = 0.15 * 30 / 0.0591

Log K = 76.142

K = 1.3 * 10^76

thus option (c) 1.3 * 10^76 is correct option.

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