Question

For integer n € {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15) function hex(n) returns hexadecimal character from F. Write function hex and use it to create the function HEX(N) that for integer N>0 displays its value hexadecimal form. For all programs use C++, and make all programs as short as possible. Write the main program that supports the following sample dialog: Enter a positive integer : 13 Hexadecimal value D Enter a positive integer : 255 Hexadecimal value Enter a positive integer ; 1234567 Hexadecimal value -120607 Enter a positive integer 10 Done!

Answer 1

ANSWERS:

As per your requirement here is the c++ code to convert an integer to hex and terminating the code if the user enters 0

Raw code:

#include<iostream> //input output stream

using namespace std; //name space standard

void Hex(int n) //hex function with one parameter

{

  char hexa_Decima_Number[100]; //char array to store the resultant hexa hexa_Decima_Number

  int i = 0; //count variable

  while(n!=0)//while loop

  {

    int temp_value = 0; //temp_value as 0

    

    temp_value = n % 16; // store remainder in temp_value variable.

    if(temp_value < 10) // check if temp_value < 10

    {

      hexa_Decima_Number[i] = temp_value + 48; //converstion of values using ascii

      i++; //incrementing i value

    }

    else//else condition

    {

      hexa_Decima_Number[i] = temp_value + 55; //to convert character values using ascii

      i++; //incrementing

    }

    n = n/16; //because its hex means 16

  }

  cout<<"Hexa Decimal value= ";

  for(int k=i-1; k>=0; k--) //to get hexa_Decima_Number in reverse order

    cout <<hexa_Decima_Number[k]; //printing

}

int main() //main

{

  int n = 1; //initialize n as 1

while(n){//while it runs infinitely because it is a true always

cout<<"Enter a positive integer: ";//prompt the user to enter integer

cin>>n;//taking input from user

if(n==0){ //if user enters 0 break the loop

cout<<"\nDone!";

break;//break

}

Hex(n);//calling the function by sending user input as parameter

cout<<endl; //to print on next line

}

  return 0;

}

code in the editor:

main.cpp saved i #include<iostream> //input output stream 2 using namespace std; //name space standard 3 void Hex(int n) //hex function with one parameter 4 { 5 char hexa_Decima_Number[100]; //char array to store the resultant hexa hexa_Decima_Number int i = 0; //count variable while(n!=0)//while loop 8 { int temp_value = 0; //temp_value as o temp_value = n % 16; // store remainder in temp_value variable. if(temp_value < 10) // check if temp_value < 10 hexa_Decima_Number[i] = temp_value + 48; // converstion of values using ascii i++; //incrementing i value else//else condition 18 hexa_Decima_Number[i] = temp_value + 55; //to convert character values using ascii i++; //incrementing n = n/16; //because its hex means 16 25 E 26 27 28 29 cout<<"Hexa Decimal value= "; for(int k=i-1; k>=0; k--) //to get hexa_Decima_Number in reverse order cout <<hexa_Decima_Number[k]; //printing } int main() //main { int n = 1; //initialize n as 1 while(n) {//while it runs infinitely because it is a true always cout<<"Enter a positive integer: ";//prompt the user to enter integer cin>>n;//taking input from user if(n==0){ //if user enters break the loop cout<<"\nDone!"; break;//break 31 a Hex (n);//calling the function by sending user input as parameter cout<<endl; //to print on next line return 0;

output:

clang version 7.0.0-3-ubuntu0.18.04.1 (tags/RELEASE_700/final) ? clang++-7 -pthread -o main main.cpp > ./main Enter a positive integer: 13 Hexa Decimal value=D Enter a positive integer: 255 Hexa Decimal value= FF Enter a positive integer: 1234567 Hexa Decimal value= 12D687 Enter a positive integer: 0 Done!

Feel free to comment in the comment section if you have any doubts or queries.

Thank you! doupvote.