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2) The following reaction is carried out at 1 atm pressure. CH:COOH () What is the equilibrium constant for this reaction at

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Answer #1

A) Equalibrium constant for above reaction :

CCHsCOOc2Hs Кс- [212

we can find Kc if value of concentration of products is given in question.IN THIS QUESTION THEY MENTIONED  CONCENTRATION VALUE OF REACTANTS ONLY.

B) now for finding composition :

  CH_{3}COOH+C_{2}H_{5}OH\rightarrow CH_{3}COOC_{2}H_{5}+H_{2}O

INITIAL MOLE: 2 2 0 0

FINAL MOLE: 2-X 2-X X X

(2-X) (2-X) (2-X)2

NOW PUT THE VALUE OF Kc FROM ABOVE AND WE GET  THE VALUE OF X WHICH IS OUR COMPOSITION .

if you want something more information then ask me in comment box.

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