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Question 29 The collector current Ic is approximately equal to . [4 Marks] +9V 3R2RE * 15 k 1.0k MB 2.17 mA 1.48 mA 2.75 mA 6

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+9v Ay- Rc 2.2k2 R2 VIE RE 1.ok2 We assume voltage drop across Re is Va. So, Vz = 9 x 15k 2.2 V Applying kVL e get Ng - VBE-

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