Question

10) Write a program that inputs five numbers and determines the number of negative numbers input, the number of positive numbers input and the number of zeros input. An easy way to create a counter is given in the example below: int counter 0; initializes the counter counter counter +1;//increments the counter each time is used. Note: Output should read as shown below where # replaces the number of inputs and it is displayed on a table format] (40 pts.) Cudhso Positive numbers : # Negative numbers: # tu Zeros numbers :#

Answer 1

#include <stdio.h>

int main()
{
int arr[5];//to store 5 numbers
int i=0,counter=0;
printf("enter 5 numbers:\n");
for(i=0;i<5;i++)
scanf("%d",&arr[i]);
//count +ve numbers
for(i=0;i<5;i++)
if(arr[i]>0)
counter=counter+1;
printf("Positive numbers :%d\n",counter);
  
counter=0;
//count -ve numbers
for(i=0;i<5;i++)
if(arr[i]<0)
counter=counter+1;
printf("Negative numbers :%d\n",counter);
  
counter=0;
//count 0's
for(i=0;i<5;i++)
if(arr[i]==0)
counter=counter+1;
printf("Zero numbers :%d\n",counter);
  
return 0;
}

8:41 PM hitesh xC IChegg.com х <D media/25d/2548c446-bl X . + Online C Compiler-onli X CSecure https://www.onlinegdb.com/online_c compiler H Save Language C OnlineGDB beta online compiler and debugger for c/c++ code. compile. run. debug. share. IDE My Projects Learn Programming Programming Questions Sign Up Login 26 27 28 29 30 31 32 for(1-9;1-5;1++) if (arr[i]ke) counter-counter+1; printf("Negative numbers :%d\n",counter); counter 0 //count e's 34 35 36 37 38 for(i-0;i<5;i++) if (arr[il0) counter counter+1; printf("Zero numbers :%d\n", counter); return 0 input enter 5 numbers: St Positive numbers :3 ative numbers :1 Adobe Creative cloud for Teams starting at $29.99 per month. ADS VIA CARBON 2cro numbers Program finished with cxit code 0 Press ENTER to cxit consolc About FAQ Blog Terms of Use Contact Us . GDB Tutorial Credits 2018 © GDB Online