Conserve momentum: initial p = final p
initial p = M*(28m/s*cos30) i + M*(12m/s - 28m/s*sin30) j
initial p = M*24.248m/s i - M*2m/s j
final p = M*(6m/s + VcosΘ) i + M*VsinΘ j
The i-components must be equal, as must the j-components:
24.248 m/s =5m/s + VcosΘ → VcosΘ = 19.248 m/s ← #1
-2m/s = VsinΘ ← #2
Divide #2 by #1
VsinΘ / VcosΘ = tanΘ = -2m/s / 19.248m/s
Θ = -5.932º (that is, below the x-axis)
V = -2m/s / sin-5.932º
Need help asap. And I only have one attempt left An open railroad car of mass...
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