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An aluminum bar has a minimum yield strength in tension and compression of 420 MPa and e = 15%. Find the factor of safety for failure by yielding if: 2. a. b· c. d· ơ,-180 MPa, Oy-180 MPa Ox = 180 MPa, Tyx-180 MPa σ,--80 MPa, Tyx = 120 MPa Tyx=120MPa

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