A potential difference of 2.00 V will be applied to a 39.00 m length of 18-gauge aluminum wire (diameter = 0.0400inches). Calculate the current. Calculate the current density. Calculate the electric field. Calculate the rate at which thermal energy will appear in the wire.
V = iR
i = V/R
i = 3.8/R
to calculate R ,
Resistance = resistivity x length/area
R = ?L/A =0.223
i = 3.8 / 0.223 = 17 A
A potential difference of 2.00 V will be applied to a 39.00 m length of 18-gauge...
A potential difference of 5.60 V will be applied to a 39.00 m length of 18-gauge copper wire (diameter = 0.0400inches). Calculate the current. Tries 0/20 Calculate the current density. Tries 0/20 Calculate the electric field. Tries 0/20 Calculate the rate at which thermal energy will appear in the wire.
A potential difference of 1.40 V will be applied to a 41.00 m length of 18-gauge tungsten wire (diameter = 0.0400 in). Calculate the current. Calculate the magnitude of the current density. Calculate the magnitude of the electric field within the wire. Calculate the rate at which thermal energy will appear in the wire.
A potential difference of 1.22 V will be applied to a 21.6 m length of 18-gauge copper wire (diameter = 0.0400 in.). Calculate (a) the current, (b) the magnitude of the current density, (c) the magnitude of the electric field within the wire, and (d) the rate at which thermal energy will appear in the wire.
8c26p58) A potential difference of 4.20 V will be applied to a 35.00 m length of 18-gauge silver wire (diameter = 0.0400inches). Calculate the current. Calculate the current density. Calculate the electric field. Calculate the rate at which thermal energy will appear in the wire.
A potential difference of 100 V is maintained across the two ends of a nickel wire of radius 2 mm and length 10 m. Calculate (a) the electric field intensity, (b) the current density, and (c) the electric current through the wire
Two pieces of 14-gauge wire (diameter=0.163cm) each are 50m in
length. One wire is made of aluminum, the other of tungsten; both
are maintained at a temperature of 20°C. The wires are joined
together at one end to form a sign wire of 100m length. A potential
difference of 12V is applied across the length of this compound
wire. (a) What is the resistance of each 50m segment? (b) What is
the current in each? (c) What is the potential...
When a potential difference of 12 V is applied to a wire 6.6 m long and 0.32 mm in diameter the result is an electric current of 2.1 A . What is the resistivity of the wire?
When a potential difference of 12 V is applied to a wire 6.6 m long and 0.33 mm in diameter the result is an electric current of 2.0 A . 1. What is the resistivity of the wire?
4a. The resistance of a 5.0 meter length of 14-gauge copper wire is 8.1 x 10 ohms/meter. How much energy loss occurs per second in the wire when a current of 20.0 amps is applied? Assume that the cross-sectional area is 2.1 mm', what is the shortest time in which the applied current could heat the wire by 15.0°C? You may assume that the density of copper is 8.92 x 10 kg/m and its molar heat capacity is 6.0 calories/mole/K....
What would the Hall voltage be if a 2.00-T field is applied across a 10-gauge copper wire (2.588 mm in diameter) carrying a 20.0-A current? A. 1.16 µV B. 21.16 µV C. 5.16 µV D. 9.16 µV