Question

A solution contains 1.10x10-2 M potassium phosphate and 5.69x10-3 M ammonium cyanide. Solid zinc acetate is added slowly to tA solution contains 9.17x10-3 M ammonium chloride and 9.44x10-M potassium sulfite. Solid silver nitrate is added slowly to th

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Q1. potassium phosphate and ammonium cyanide

(A.) formula = Zn3(PO4)2

(B.) [Zn2+] = 4.22 x 10-10 M

Q2. ammonium chloride and potassium sulfite

(A.) formula = AgCl

(B.) [Ag+] = 1.96 x 10-8 M

Explanation

Q1. Given : concentration of potassium phosphate = [K3PO4] = 1.10 x 10-2 M

[PO4 3-] = [K3PO4] = 1.10 x 10-2 M

Ksp Zn3(PO4)2 = [Zn2+]3[PO4 3-]2

9.1 x 10-33 = [Zn2+]3 * (1.10 x 10-2 M)2

[Zn2+]3 = (9.1 x 10-33) / (1.10 x 10-2 M)2

[Zn2+]3 = 7.52 x 10-29

[Zn2+] = (7.52 x 10-29)1/3

[Zn2+] = 4.22 x 10-10 M

Given : concentration of ammonium cyanide = [NH4CN] = 5.69 x 10-3 M

[CN-] = [NH4CN] = 5.69 x 10-3 M

Ksp Zn(CN)2 = [Zn2+][CN-]2

8.0 x 10-12 = [Zn2+] * (5.69 x 10-3 M)2

[Zn2+] = (8.0 x 10-12) / (5.69 x 10-3 M)2

[Zn2+] = 2.47 x 10-7 M

Since less concentration of Zn2+ is required to precipitate phosphate, therefore, Zn3(PO4)2 will precipitate first.

Add a comment
Know the answer?
Add Answer to:
A solution contains 1.10x10-2 M potassium phosphate and 5.69x10-3 M ammonium cyanide. Solid zinc acetate is...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT