molar mass of Rubidium = 85.4678 g/mol
let fraction of 84.911794 isotope be x
then, fraction of 86.909187 isotope will be 1 - x
use,
x*(84.911794) + (1-x)*(86.909187) = 85.4678
84.911794x + 86.909187 - 86.909187x = 85.4678
1.997393x = 1.441387
x = 0.72
since, x is 0.72 it mean 84.911794 isotope is 72%
hence, 84.911794 isotope is most abundant
Answer : option a
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