Question

Trig Word problem

A plane flying a straight course observes a mountain at a bearing of 30.2° to the right of its course. At that time the plane is 8 kilometers from the mountain. A short time later, the bearing to the mountain becomes 40.2". How far is the plane from the mountain when the second bearing is taken (to the nearest tenth of a km)? O A. 10.3 km OB. 6.2 km O C. 11.7 km OD. 4.2 km

Answer 1

Sam ,139.99 0 x 30.2° ON 40-2° from Aomn L0 = 180°- 40-2° - 139.8° Now using sine Law im AOmn MN - ON a om simo Simm SimN s om sim 139.8° Sim 30.2° - om- & sim 30.2° Sim 139.89 Tol = 6.23 km a 6.2km The plome from the mountain is 6.2 km far.