Ans 7:
Total pressure of the mixture = PT = 210 atm
Let the number of moles of N2 in the mixture be = n1 = 31 moles
Let the number of moles of H2 in the mixture be = n2 = 93 moles
Let the number of moles of NH3 in the mixture be = n3 = 13 moles
Let the total number of moles in the mixture be n = n1+ n2 + n3 = 31 + 93 + 13 = 137 moles
Mole fraction of NH3= n3/n = 13/137 = 0.0949 = χNH3
Partial pressure of ammonia = χNH3 x PT = 0.0949 x 210 = 19.929 atm.
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