A) Angular momentum of the bike tire-
The angular momentum of the bike tire remains constant as the angular momentum is the moment of inertia times angular velocity. So when person flip over the wheel the effective mass increases but angular velocity decreases by the same ratio so the angular momentum of the bike tire conserves.
B) Moment of inertia of the bike tire-
The moment of inertia of the bike tire increases because it is the ratio of the angular momentum with the angular velocity and here the angular momentum of the bike tire is constant and angular velocity decreases so we get a gain to tha moment of inertia of the bike tire.
C) Angular momentum of the bike tire and me -
The angular momentum of the whole system always remains conserve. In any case if one lose the angular momentum, the other one will gain the same amount. But the total angular momentum remains constant.
D) Kinetic energy of the system of bike tire and me -
The kinetic energy of the system is directly proportional to the magnitude of angular momentum and inversely proportional to the moment of inertia here we have constant angular momentum and a gain in the moment of inertia so the kinetic energy of the system will decrease as comparison to before.
In an in-class demo, I sat on a stool with a spinning bike tire. I was...
A student holds a spinning bicycle wheel while sitting
motionless on a stool that is free to rotate about a vertical axis
through its center (see the figure below). The wheel spins with an
angular speed of 16.1 rad/s and its initial angular momentum is
directed up. The wheel's moment of inertia is 0.110 kg ·
m2 and the moment of inertia for the student plus stool
is 3.30 kg · m2.
(a)
Find the student's final angular speed (in...
A person sits on a frictionless stool that is free to rotate but is initially at rest. The person is holding a bicycle wheel (I = 3 kg*m2) that is rotating at 8 rev/s in the clockwise direction as viewed from above, and the moment of inertia of the person-wheel-stool system is 9 kg*m2. For this problem, all answers involving a rotational component will be expressed in revolutions rather than radians. 1. What is direction of the angular momentum of...
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You are sitting on rotating stool, spinning freely. The bearings of the seat which allow you to spin are frictionless. Without touching any other part of the stool, which of the following things could you change by moving your arms, legs, head or torso? The location of your center of gravity. Your angular momentum. Your mass. Your rotational kinetic energy. Your total kinetic energy. Your weight The horizontal component of your linear momentum. Your moment of inertia. Your...
Consider the demo that you saw in class, in which a person stands on a platform that is free to rotate. They are initially at rest. Someone hands them a bicycle wheel of radius r = 30 cm that is full of concrete, and thus has a mass of m=4kg You may model the person as a cylinder (I=1/2mr^2) of mass 80kg and radius 20 cm. Suppose that the bike wheel is initially spinning horizontally at an angular velocity of...
In of the lectures, the instructor invited the lab technician to present a few demos. In one of them, the technician was sitting at rest on a stool which could rotate freely and was holding a spinning wheel. Upon turning the wheel upside-down, the technician started to rotate. This is a consequence of the conservation of linear momentum force angular momentum mechanical energy moment of inertia
A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4.7 kg⋅m2 . A second student tosses a 1.7 kg mass with a speed of 3.0 m/s to the student on the stool, who catches it at a distance of 0.50 m from the axis of rotation. A) Calculate the initial kinetic energy of the system. B) Calculate the final kinetic energy of the system.
4 A ballerina is spinning on one foot with her arms stretched out, when she pulls her arms in. Will the following quantities increase, decrease or remain unchanged? (Ignore air drag) (i) Her angular speed. Increase (ii) Her moment of inertia. Decrease (iii) Her angular momentum. Increase (iii) Her rotational kinetic energy. Increase. K1 = 1/2 I1ω1 ; K2 = 1/2 I2ω2 . Because I1ω1 = I2ω2 , it follows K2 = (1/2 I1ω1)(I1/I2) = K1(I1/I2) > K1 THE ANSWERS...
1. A pottery wheel with moment of inertia I = 0.14 kg m2 is spinning at 5 radians/sec. How much kinetic energy does it have? 2. Ceres is the largest asteroid in the belt between Mars and Jupiter. It has an average radius of 475 km and a period of rotation of 9.07 hours. Calculate its angular momentum if the mass is 9.42 x 1020 kg The moment of inertia of a solid sphere I = 2/5 mR2
On an old-fashioned rotating piano stool, a woman sits holding a pair of dumbbells at a distance of 0.560m from the axis of rotation of the stool. she is given an angular velocity of 2.75rad/s , after which she pulls the dumbbells in until they are only 0.160m distant from the axis. the woman's moment of inertia about the axis of rotation is 4.50kg*m2 and may be considered constant. Each dumbbell has a mass of 4.80kg and may be considered...
On an old-fashioned rotating piano stool, a woman sits holding a pair of dumbbells at a distance of 0.640 mm from the axis of rotation of the stool. She is given an angular velocity of 2.60 rad/srad/s , after which she pulls the dumbbells in until they are only 0.165 mm distant from the axis. The woman's moment of inertia about the axis of rotation is 5.00 kg⋅m2kg⋅m2 and may be considered constant. Each dumbbell has a mass of 5.00...