Question

An automobile of mass m=1600kg travels at a speed of of 35 km/h. when the driver jams on the brakes, causing all four wheels to lock, the automobile skids to rest in 7m. determine the magnitude of the normal reactions and of the friction force at each wheel as the automobile skidded to rest. CG is 400mm from surface and 1200mm away from both wheels a and b.

Answer 1

mass of Automobile {m} = 1600 kg. initial velity (V) = 35 km/h = 9.72 m/s Stopping distanco(s) = 7 m Tim 3213 Step 12 frost calculate acceleration during skinuing · v2 = vo +20() 0 - 69-42+ 2017) (a = -6.75 m/s² step (9): FBD of Automobile lepas tig - may = m(o) 6.4mo t weig TNB Sobe FB WSM NA + NB - W =0 ... NA + NB = W - 0 Et = n19n) = max 1:27 12 m UA IL FA+ FB = man U U U MINA + NB) = mye - © diw) = max [from equution ] 6.75 .: M = 9. = 9.61 = 0.688 M is coefficient of frictim between wheel and Road- about wheel 'A'. E take moment EMA =0 NB(2.4) – W[1.2) + mare (0.4) = 0 Ng (2.4) – 1600 (9.81) (1.2) – 16016-75) (0-4) = 0 NB = 9648 newton → N font = Ne = 4824 N from eakatım NA = mg - NB = 160119181) – 9648 = 6048 N Near - = 3024 N Frear - Il Near = 0.688 (3024) - 2080.5 N) Front - \ N front = 0.688 ( 4824) - 3318.9 N

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