Question

Question 1 (1 marks) Tron (II) sulfide can react with carbonic acid, H2CO3, according to the reaction shown. 2 FeS (s) + H2CO3 (aq) + 2 FeO (s) + 1/n (CH2O)n (aq) + 2 S (s) NO a) Calculate the mass (g) of iron (II) oxide produced when 10.20 g iron (II) sulfide and 1.450 mol carbonic acid are reacted. The reaction results in a 87.5 % yield of product formed. b) If the carbon containing product has a molar mass of 2.10 x 102 g/mol, determine the molecular formula for the carbon containing product. To answer part b of the question, try to think of how you can determine a molecular formula from an empirical formula.

Answer 1

9.) 2Fes (8) + H2CO3(ap.) —— 272018) + +(0120), +25(%) no Given man of Fes= 10.20g molar manj Fes = 87-91. molof Fes= given mass molar mass = 10.208 87.91 fmort = 0.116 mol

imol of HCO3 huqu with 2 molfer 1.450 mol of hoz rent with 2.9 mol Fes But moly Fes available = 0 Almol so Fes is Limting reagent and consume completely in reachion. Reaction proceed according to Fes 2 mol of Fes give 2 mol Feo 0.116 mol of Fes give 0.116 mol Feo mol y feo produced = 0.116 mass of feo = mol x molar mas - 0.116 motx 77.8448 = 8.339 so thoeretical yield = 8.339 of gield = experimental Yield -X100 thoeretical yieed 87.5 = Experimental Yielt viso 8:334 87-588.33g = Joo experimental yield Experimental yied = 7.29 g Answer

Molecules formule = nx (empirical formule) nis integer can be Calculated as n= Molecular mass of Molecules formula Molecully mass j empirical Formule Molecules mass of moleculer Formule = 2 10x10 9 A empirical Formula = CH2O = molar mass 30'02 9 mol n = = 6.997 2.10x10² gjorol 30:02 globi n= 7 7 (CHO) moleculpo formula = = ( 40 Дruu