Question

Question 4 1 pts The New York Times reported that the mean time to download the homepage for the Internal Revenue Service is 0.75 seconds. What is the probability that it takes you more than 3 seconds to download the page? (Use an exponential distribution to determine this probability.) - 0235 Use the following information to help you: e1=.9048 -4 = 6703 -08=.4493 -16 - 2019 -0498 e-016 = .8465 -0.417 – 6592 -0.83 -.4346 -1.667 – 1889 -3333 = .0357 e-62 - .8187 2048 = 6376 09.4066 e-- 1653 e-028 - .7788 03 = .6065 e' = -3679 € = .1353 e-0183 e-026 = .7659e46 = 5488 e 12 = .301262 = .1054 = .0067 e-03 - .7408 -0.625 - 5353e-125 = 2865 e 4 - 0907 - .0024 e-0.383 - .7165 20667 - 5134 -1.393 - 2636 e -0821 e-0003 e-0375 - .6873 -0.75 -4724 -3 -2231 2-207 - 06952-10-.0000 8946 7788 0.9817 OO 0.1054 2212 0183

Answer 1

Let X be the number of seconds it takes to download the page exponentially distributed with the parameter 2-1-1=1.3333 10.75 The required probability is p(X> 3)=e-2x = 0 -1.3333(3) = 2–3.9999 = 6 + =0.0183