A student standing on a train station observes that the pitch of the train decreases from 900.3 Hz to 880.3 Hz as it travels past the student at a constant speed. What's the speed of the train? (Assume the velocity of sound is 333 m/s).

Given that
frequency f=900.3 Hz
appreant frequency f'=880.3 Hz
now we find the speed of the train
f/f'=v+vs/v-vs
900.3/880.3=333+Vs/333-Vs
299799.9-900.3Vs=293139.9+880.3vs
6660=1780.3Vs
Vs=3.741 m/s
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