Question

Time Remaining: 14:14 4 the pressure is 0.72 atm, then the new volume is 1.8 L. What is the temperature in °C) of the air at this elevation? 2 points In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.20 atm, how many moles of steam are in the cooker? 5 ( 2 points That a gas increases in pressure as its volume decreases is a statement of 2 points The pressure in Denver, Colorado averages about 632 mm Hg. How many atmospheres is this? 2 points A balloon at 30.0°C has a volume of 222 mL. If the temperature is increased to 53.1°C and the pressure remains constant, what will the Homes End Esc

Answer 1

5) volume of gas in. Pressure cooker V= 4.00L Temperature T = (115€ +273) T= 388 K : : Pressure of gas. p= 3.20 atm Let' the gas in pressure cooker is Ideal gas. According to ideal gas equation, - PV=nRT n= Number of moles of . ..gas R= Universal gas constant ::: n eo 20.0821 Lätm mortky = (3.20 atm) (4.00L) - [0.0821 Lammo"k)(388K) | ne / 12.8 atm, L ) (31.8548 atm, limoiy) n= 0.402 moles. 'The number of moles of steam = 0.402 motes 6) The relation between Pressure and volume is stated in Boyle's LAW. A constant temperature, A gas increases in pressure as it's volume decreases with fixed amount is a statement of Boyle's LAW. Pat (At constant T&n) PV = constantl. ni number of moles Ti Absolute temperature P: Pressure Vi volume, Vitom ,

Đ The pressure in Denver p = 632 mm Hj. I atm = 760 mm Hg 760 mm Hg 632 mm Hg equals to equals to 1 atm. ? .. . ... Pressure in atm = (1 to X 632 mmHg) 760 mm Hg Pressure in. atmi = 0.8316 atm 8) Initial temperature T=130.0+273) - 303 k Volume of the gas V, = 222 mL Final temperature T2 = (53.1 C+273) = 326.1k let, Final volume of the gas is V₂ At constant pressure for fixed amount of gas Volume of gas is directly proportion to Absolute temperature. This known as CHARLES' LAW. : divat (at constant P&n). - ) = v= 694. 2xv1 = (sed k) x 230 1 Vg = 238.9 m2