Question

m = 14 16 mm ng 1.8 mm screen 1 m

In the Young’s Double Slit experiment above (set up in air), light of wavelength 546 nm falls on the two slits. However for the top slit the light has to pass through a glass container of length 16 mm containing a gas of refractive index ng. When this happens it is observed that the central maxima (corresponding to equal path distances) moves to the position of the 14 maxima if glass container was not present.

Determine the refractive index of the gas if the refractive index of air is 1.000275.

Answer 1

7 cenrrol Bright position of central fringe Bright shits to m=14 fringe, m=14 be teen difference due to glass container = position this means at the Bright fringe must be (Mree-1) + width or t- thickness of container. .. At position where initially as right fringe was present, the path differe Given abone m= 14 manima forms at this position. :. Ax = 142 ( 1) + = 144 Mair =) Mg = ( 14 2 + 1) Mair = (4x5467909 + 1) 1.00 1.000 275 148 54 6X 16x10-3 1.000753 53 1.000