Question

The data shown to the right are from independent simple random samples from three populations. Use these data to complete parts (a) through (d). Sample 1 Sample 2 Sample 3 Click the icon to view a table of values of Fa Calculate SST, SSTR, and SSE using the computing formulas. SST = SSTR= SSE (Type an integer or a decimal. Do not round.) (Type an integer or a decimal. Do not round.) (Type an integer or a decimal. Do not round.) b. Compare your results in part (a) for SSTR and SSE with the following results from the defining formulas. SSTR2 - x)2 = 42.9 and SSE (0-1) s = 102 When the value of SSTR is found by using the defining formula, it the same value as when it is found by using the computing formula. When the valu of SSE is found by using the defining formula, it V the same value as when it is found by using the computing formula c. Construct a one-way ANOVA table. Source df SS M S F-statistic Treatment Error Total (Type intecers or decimals rounded to two decimal places as needed.) Click to select your answer(s).

Answer 1

ANOVA Formulas One-Way ANOVA Table Sum of Squares Mean Square Degrees of Freedom Source F-Stat P-Value DE ss MS Right tail of Between Groups k-1 SSB MS8 = SSg/(k – 1) F = MSg/ MSW F(k-1,N-k) Within Groups N-K SSW MSW = 55w/(N – k) Total: N-1 SST = SSg+SSW

Analysis of Variance Results F-statistic value = 6.43106 P-value = 0.01264 Groups Group 1 Std. Error Data Summary Std. Dev. 4.1593 Mean 5.4 2.8 2.3875 Group 2 Group 3 1.8601 1.0677 1.5362 10.4 3.4351 ANOVA Summary Sum of Squares Degrees of Freedom Mean Square Source F-Stat P-Value SS MS Between Groups 149.2 74.6 6.4311 0.0126 Within Groups 139.1994 11.5999 Total: 14 288.3994 One-Way ANOVA [Average + Standard Deviation] Group 1 Group 2 Group 3

Ho ll, = ll. 4 ti: , # , # Hz Significance level () - 56%. = 0.05 Critical value F* . 4.7374 F f Otherwisey Do not Reject Ho, F: 6.4-3106 P-value = 0.0126 / from F-table e value >x. do not reject Hoo The data do not have sufficient evidence to conclude that the population means are not all the same. 1. Hence, we conclude that the three treatment means do not differ significantly, the data are Consistent with the Hol am new nor in HomeworkLib family Plz Support me. plz like. CS$canned with camihanker you li.