A 0.507 m string connects a 0.265 kg puck to a peg at the center of...

Question

Question

A 0.507 m string connects a 0.265 kg puck to a peg at the center of a frictionless air table. The puck moves in a horizontal,

science physics

Answer 1

Answer #1

Option (G) is Correct.

In given problem

Tension T in string provides the centripetal force for puck to rotate in circular path.accelaration of puck can be find as followes.

$T=\frac{mV^{2}}{r}$

T=ma since, $a=\frac{V^{2}}{r}$

$a=\frac{T}{m}$

Given, length of string ,8=2=0.507m mass of puck, m = 0.265 kg string Tension, I = al.in magnitude of accelerction of the luc

Answer 2

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