Question

Derive R=v20sin2θ0/g for the range of a projectile on level ground by finding the time t...

Derive R=v20sin2θ0/g for the range of a projectile on level ground by finding the time t which y becomes zero and substituting this value of t 12 into the expression for x−x0, noting that R=x-x0

0 0
Add a comment Improve this question Transcribed image text
Answer #1

L 220 26 a ER No is speed of 1 ay projection o is angle of projection. Along y asis Initial velocity is My = Vosing AcceleratAlong x aseis: Initial velocity is [ehe = Vocoso Acceleration is tot ... Displacement 4x in time to is : As = XoXo = Use tq t

Add a comment
Know the answer?
Add Answer to:
Derive R=v20sin2θ0/g for the range of a projectile on level ground by finding the time t...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • derive an expression for the time that it takes the projectile to stick to the ground...

    derive an expression for the time that it takes the projectile to stick to the ground given the constant air resistance. A=1/2ϵg B = -Vox C= x t = the quadratic formula t = -B²+- sqr(B²-4AC)/2A how to solve for t?

  • At time t = 0, a projectile is launched from ground level. At t = 2.00...

    At time t = 0, a projectile is launched from ground level. At t = 2.00 s, it is displaced d = 51 m horizontally and h 76 m vertically above the launch point, what are the (a) horizontal and (b) vertical components of the initial velocity of the projectile? (c) At the instant it reaches its maximum height above ground level, what is its horizontal displacement D from the launch point?

  • VBA The projectile motion equations are,x=x0+v0*cos(θ)*t, y=y0+v0*sin(θ)*t+0.5*g*t^2 where x and y are the current position at...

    VBA The projectile motion equations are,x=x0+v0*cos(θ)*t, y=y0+v0*sin(θ)*t+0.5*g*t^2 where x and y are the current position at time t, x0 and y0 are the projectile’s initial position, v0 is the projectile’s initial speed, θ is the initial firing angle of the projectile, and g is the gravitational acceleration which is -9.81 m/s2 near Earth’s surface. The user (me) will input the initial x-position (m), y-position (m), speed (m/s), the firing angle (in degrees) in cells F2-F5 on Sheet2. Create a run...

  • 6. A projectile is fired from ground level, and 10 seconds later hits a target 374...

    6. A projectile is fired from ground level, and 10 seconds later hits a target 374 m away and 45 m above the ground. What were the initial velocity and launch angle? 7. The horizontal velocity of a projectile is assumed constant, vx vo cos Bo. The vertical velocity of the ball can be written as a function of time, vy(t)- vo sin 8o + ayt, where the acceleration ay in the y-direction is assumed constant. a. Set the origin...

  • ​To understand how to apply the equations for one-dimensional motion to the x and y directions

    To understand how to apply the equations for one-dimensional motion to the x and y directions separately in order to derive standard formulas for the range and height of a projectile. (Figure 1) A projectile is fired from ground level at time t=0, at an angle with respect to the horizontal. It has an initial speed vo. In this problem we are assuming that the ground is level. Part A Find the time tH it takes the projectile to reach its...

  • Example 4.3 A Bull's-Eye Every Time In a popular lecture demonstration, a projectile is fired at...

    Example 4.3 A Bull's-Eye Every Time In a popular lecture demonstration, a projectile is fired at a target in such a way that the projectile leaves the gun at the same time the target is dropped from rest. Show that if the gun is initially aimed at the stationary target, the projectile hits the falling target as shown in figure (a). The velocity of the projectile (red arrows) changes in direction and magnitude, but its acceleration (purple arrows) remains constant....

  • A projectile is launched from level ground at an angle of 30 degrees to the horizontal....

    A projectile is launched from level ground at an angle of 30 degrees to the horizontal. If the magnitude of the launch velocity is 30 m/s, calculate the time rate of change in speed and radius of curvature when t=1, 2, and when the projectile is at its max height. Please do the problem how the description says to do it below and put the answer neatly in a table format. Thank you. 2) A projectile is launched from level...

  • Learning Goal: To understand how to apply the equations for one-dimensional motion to the x and...

    Learning Goal: To understand how to apply the equations for one-dimensional motion to the x and y directions separately in order to derive standard formulas for the range and height of a projectile. (Figure 1) A projectile is fired from ground level at time t=0, at an angle ? with respect to the horizontal. It has an initial speed v0. In this problem we are assuming that the ground is level. a)Find the time tH it takes the projectile to...

  • ------******Don't use R=v^2sin2ø/g******------- A small--------Don't use R=v^2sin2ø/g--------------- projectile...

    ------******Don't use R=v^2sin2ø/g******------- A small--------Don't use R=v^2sin2ø/g--------------- projectile is launched from ground level with an initial speed of 98 m/s. Find the possible angles of elevation so that its range is 490 m.********* Don't use R=v^2sin2ø/g***********It's not a physics problem. Use accel,velocity,position vectors. a,v,t. --------Don't use R=v^2sin2ø/g-------

  • G. Derive an expression for Ground Resistance of a hemisphere of radius "r" buried in soil...

    G. Derive an expression for Ground Resistance of a hemisphere of radius "r" buried in soil with soil resistivity p.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT