Question

A 250 g ball with a speed of 5.0 m/s strikes a vertical wall at an angle of 30° to the surface and rebounds at the same angle with the same speed.. The ball is in contact with the wall for 10 ms. What is the impulse on the ball?

Choose correct answers:

1.25 N s

2.5 N s

4.33 N s

5.0 N s

Answer 1

Here ,

as the momentum in the direction parallel to the wall will be constant

the force will be perpendicular to the wall

Using second law of motion

Impulse = change in momentum

impulse = 0.250 * (v * sin(theta) - (- v * sin(theta)))

impulse = 0.250 * 5 * (sin(30) - (- sin(30)))

impulse = 1.25 N.s

the impulse acting on the object is 1.25 N.s