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A producer of a certain type of electronic component ships to suppliers in lots of twenty....

A producer of a certain type of electronic component ships to suppliers in lots of twenty. Suppose that 60% of all such lots contain no defective components, 30% contain one defective component, and 10% contain two defective components. A lot is picked, one component from the lot is randomly selected and tested.
What is the probability that the randomly selected item is nondefective?

math   Statistics-And-Probability   
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Answer #1

probability that the randomly selected item is nondefective

=P( no defective component lot)*P(nondefective | no defective component lot)+P(one defective component lot)*P(nondefective | one defective component lot)+P( two defective component lot)*P(nondefective | two defective component lot)

=0.6*(20/20)+0.3*(19/20)+0.1*(18/20)

=0.975

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