A mass mA = 1.4kg , moving with velocity v? A=(5.0i
here ,
mA = 1.4 Kg
uA = 5i + 4.6 j - 3k m/s
mB = 3.8 Kg
vA = -3 + 3.4 k m/s
Now , using conservation of momentum ,
mA*uA = mA*vA + mB*vB
1.4 * (5i + 4.6 j - 3k) = 3.8 * vB + 1.4 * (-3i + 3.4 k)
solving for vB
vB = 2.95 i + 1.69 j -2.36 k m/s
the velocity of mass B is (2.95 i + 1.69 j -2.36 k) m/s
Question 3 (10 marks) A car A of mass ma is moving at a velocity VA to the right. It collides and sticks to car B of mass moving in the same direction as car A with a velocity V. After collision, the two cars have a velocity equal to % (VA + Vs). What is the relationship between maand me?
A 0.75kg mass moving with a velocity of v,=1.2 –3.4j m/s , strikes a 2.4kg mass moving with a velocity of v2=0.58 jm/s . Assume the collision is inelastic. a. Calculate the speed of the combined mass after the collision. b. Calculate the angle (relative to the x axis ) of the trajectory of the combined mass after the collision. a. 0.466 m/s; b. – 52.1°
A bumper car with mass m1-119kg is moving to the right with a velocity of v-4.5 m/s. A second bumper car with mass m2- 84 kg is moving to the left with a velocity of v2- 3.7 m/s. The two cars have an elastic collision. Assume the surface is frictionless
The kinetic energy, KE, for an object of mass m, moving at velocity v is represented with the equation KE is equal to (1/2)(mass)(velocity)^2 Write the kinetic energy equation using a mathematical equation. Include: • The symbols for mass and velocity. • The Math Equation Function to write 1/2 in the fraction format. • Use the superscript format to write (velocity)^2.
An object (A) of mass mA = 29.5 kg is moving in a direction that makes angle of 30° north of east with a speed vA = 5.20 m/s, while object (B) of mass mB = 18.0 kg is moving due south with a speed vB = 8.00 m/s. The two objects collide and stick together in a completely inelastic collision. Find the magnitude of the final velocity of the two-object system after the collision.
(3) A body moving so that,at time t,it's mass is m, it's velocity is v and the resultant force acting on the body is F. Suppose that at this instant, a particle of mass om and velocity u coaleces with the body so that, at time ot, the body has the mass m + Sm and the velocity v + öv. Prove that Fma (v- D-u a. A body with initial mass rn is projected vertically upwards with speed where...
5. A mass m is moving horizontally along a nearly frictionless floor with velocity v. The mass now encounters a part of the floor that has a coefficient of kinetic friction given by u. The total distance traveled by the mass before it is slowed by friction to a stop is given by (A) 2v2 lug (B) v2 /2018 (C) 2ugu? (D) HU2/2g zas=v²_v²
A hammer of mass m = 0.45 kg is moving horizontally at a velocity of v = 6.5 m/s when it strikes a nail and comes to rest after driving the nail a distance Δx = 0.95 cm into a board. What is the duration of the impact, in seconds, assuming the acceleration of the hammer was constant? What was the average force, in newtons, exerted on the nail?
An object of mass 2.75 kg is moving with a velocity v = (3.00î 5.30k) m/s. What is the angular momentum of the mass relative to the origin when it is at the location (1.60, -1.60, 1.60) m? (Express your answer in vector form.) L =E kg m2/s Additional Materials eBook
A) An object of mass 2.75 kg is moving with a velocity
v = (3.50î −
5.20) m/s.
What is the angular momentum of the mass relative to the origin
when it is at the location (1.50, −1.50, 1.50) m? (Express your
answer in vector form.)
L = ? kg · m2/s
B) Suppose you start an antique car by exerting a force of 270 N
on its crank for 0.315 s. What angular momentum is given to the
engine...