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6. The mean cost for a home nationwide is reported to be $80,000 with a standard...

6. The mean cost for a home nationwide is reported to be $80,000 with a standard deviation equal to $9,500. To test that the mean in Omaha is less than the national mean, 35 homes for sale are randomly selected and the mean is found to be $65,000. Assuming the variability is the same locally as nationally, write the appropriate null and alternative hypotheses for this situation, calculate the p-value for the test, and write your conclusion.

7. For a national compliance test for diabetics, μ = 74 and σ = 4. To test that diabetic patients at a particular hospital have this mean versus a value different than the national mean, the test is administered to 50 diabetic patients at the hospital, and x = 78.5. Assuming the variability in test scores at the hospital is the same as that nationally, find the p-value for this hypothesis test, and write your conclusion.

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Null hypothesis: Ho: μ-S80.000 That is, the mean cost for a home nationwide is reported to be $80,000 Alternative hypothesis: Ha : μ < $80,000 That is, the mean in Omaha is less than $80,000 Rejection rule If p-value α(-0.05). then reject the null hypothesis Ho Excel add-in (Mega Stat) procedure:

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