Question

4. (10) Let 32 – 7 5(2): 22 – 52 + 6 Find the Laurent expansion for f which is valid in ann(1;1, 2).

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Answer 1

Solve solve kle find Laurent expansion for f(2) where F1Z) f . 32 32-7 - and and : 2²5276 ann (1; 1,2) or region R={240:12124142} " i in de Noia .! . 12) . 32-7 . Z45276 (2-4) (2-3) (2-4) (2-3) partial fraction) »), 97-7-12-a) + 23) (24)(2-3)

2 1 = (ਪਰ , .. R ਨੇ ? : 6 : : |ਣ - ੨ , Take the bigger term as common t ]- [1-7 [1ਉਜਵੇ - ]-[++ + ਲਿਆ ਹੈ । ]-[1+ + - ] LA, . |