Question

Q8: Find the values of Iand Vin the circuits in Fig. 8. (diodes are ideal) +5 V +5 V 2.5k Σ 2.5kg 2.5 ΚΩ + -5V (a) (b) (c) = +5V +3 yo Π +2 Vo- A ΙΚΩ +1 νο- α +3 Vo- 25 ΚΩ K 1 ΚΩ +2 Vo- +IVO -5V (d) (1) + 5V +5V +3V 10 ΚΩ 10 ΚΩ ξ 10 ΚΩ α K 10 ΚΩ 20 ΚΩ 10 ΚΩ: 10 ΚΩ Hli HI Η = (g) (h) Fig. 8

Answer 1

I (2.5kor1-5=0 Given +5v Tts 2-skor Since Diode is ideal, so it act as shortcht path -5+1(2:52nt=0 Vo I s 2.5k Zero I = 2mA T. Voltage's level act as open in circuit be TS L& 2.5k I Dinde is off- (RB). Hence No current flow thro it through vo jie Iso 1 Hence Vo=50 C) + Diode is Reverse Biosed, - I Hence, I=0 and From ckt, -Sự –y 2.54 T V=57 3-5v di 4 7 Ž Dooda is in Forworld Bias -attence, v=0 I and 2.5th 2 MA I= 5 2.51

+3vt Here 3 vis Fuß t2u x W, 2V Diode =R.B There Vo=3 tivo I Lelke I 3 1 ir -3MA - +5V Diode Low Voltuge ofbes Less Ik opposition HI 30A F Hence v= 1 V +2 * 11-K I= 5-) |L-ட I= yma