Question

In a refrigeration cycle showed in the figure below, refrigerant 134 was used as the working fluid to remove 1. heat from the cooling chamber (condenser). The refrigerant was flowing through a pipe having inside diameter 11mm during the whole cycle. Just after expansion, the refrigerant was found to be a mixture of liquid and vapor in which liquid is found to be 60%. The mixture was flowing with a velocity of 164 ft/sec at pressure of 0.2 Mpa. Calculate the quality and mass flow rate of the refrigerant in the cooling cycle just after expansion. (Points 10) Condenser may be Compressor water-cooled or air-cooled Vapor Vapor Evaporator Condenser Warm Cold air air Fan Expansion LiquidVapor Liquid Valve TYPICAL SINGLE-STAGE VAPOR COMPRESSION REFRIGERATION

Answer 1

Solution -

1. The Values for refrigerant has been taken from standard thermodynamic table. You can verify if you want.

2. The specific volume is the quantity which is reciprocal of density .

3. The V' is the specific volume while V is velocity . Please don't confuse.

If you finds the solution crisp clear conceptual and easy to understand please give a good rating to the answer and provide your valuable feedback in comment section below.

Solution Images -

Coires 999999999 P= 0.2 MPa. % of liquid in liquid rapour mixture = 60% Velocity of flow of mixture = loufel sec = ug. 9872 m/s [fft/ sec = 0,3048 m/s) Properties of refrigerant R134a at 0.2 MPa. P: 0.2MPa (2001pg) Tsat= - 10.1°C VFD 010007534 m3/icg ng= 0.0999 ml kg. calculation of quality » It es defined as the mass fraction of vapour present en mixture mass fraction of rapourt mass faction of . liquid mass fraction of liquid = Percentage of liquid - 60 o of -1 100 100 0.6 mass fraction of vapour = -0.6 = 0.4 anality refrigerant

calculating mass flow rate specific volume of mixture a specific volume of - liquid + cuality & (specific volume specific volume of of vapour - liquid) si →VE Vp + xcg- Vf) 3 00007354 to.410.0999 -0.0007354] v= 0.04848124 m² lieg specific volume Mass flow rate = Density & Areax relocitie - P. Any e-density (m3/1ag) DA? Area. (m can also be written as La velocity (m/s) Eura specific rotune can AaV FHLARI spe volane Density) 95. 033x10 "x49.9872 0.04040124 ) 11.7581 m/s Mass flow rates 11.7581 m/ specific - 1 Aa Area (m2) [ + x 17% 10% - 95.0338104 [ 1= velocity (on/one L 49.9872 m/s] TL

Thank you student.