Question

Structural Analysis: 30 KN 7 |30 KN 16 0; 30 KN 04 02 15 KN 20 KN 0 D 4m 4 V4 V2 D2 3.5 m Di 4m D4 3 m Vs 2.5 m 2.5 m Vi A U U2 U; UA R 1 2 3 4x4.5m=18m Calculate each bar force of the O3, D3, U3, V4 ve 04 03 D3 U3 V4 04

Answer 1

Determine Вх and By <Exc Вх. + {[ 15x0] EM @ A=0 2 30x4.5] + [30x9] +30x13.5 + [ 20 x 18] } 18 By By = 65 KN ↑ Take Vertical cut passing through members D3 and Uz. 30 kr 7 20 KN B Foz 8 4m rozt 12.5m Fuz B. 3 4.5m 1 By =65 kr o x = tant (4.5 4 = 48.37 P = O tant Clarion 6-34 13.5

Take. ŹM @ Joint 7 =0 [ 2=6 [ 20x4.5] + [ FUz x 4] = (65x4.5) 50.625 kn Tension FUz - Ź Fx zot tre) FO3 cosß +Foz sin & - FUz - FO3 cosß + Foz sina 10. - 50.625 oor (1) EFY =o t = 1) FO3 sin ß + FD 3 cosa = 65-30-20 (2) Solve Egis. cl) and (2) FO3 = -77.6210 kr F D3 35.4823 KN -Ve- compression tve :- Tension

Joint 7 30 kN (7) 77.6210 kN/L Fo4 Eve 35.4823 = tan KN 4.5 @ = 18.43 E Fx = 0 ( tve) rcoso. 77.62 10 cosß +FO4 = 35.4823 sin a FOL - 50.6250 KN / coso =-53.3619 KN -re - compression Ź Fy =0 (4=?) (30 + ( For sino) + Fr4 + 35.4823 cos = 77.6210 sin ß -53.3619 sino Fy4 = -28. 1298 KN -re - compression